Question

If c²+6b=7,8a-b²=23 and 10c-a²=34 then a+b²+c³=

Answer 1

Given info : c² + 6b = 7, 8a - b² = 23 and 10c - a² = 34.

To find : the value of a + b² + c³ = ?

solution : c² + 6b = 7 ...(1)

8a - b² = 23 ...(2)

and 10c - a² = 34 ...(3)

from equations (1) , (2) and (3) we get,

(c² + 6b) - (8a - b²) - (10c - a²) = 7 - 23 - 34

⇒(a² - 8a) + (b² + 6b) + (c² - 10c) = -50

⇒(a² - 8a + 16) + (b² + 6b + 9) + (c² - 10c + 25) = -50 + 16 + 9 + 25 = 0

⇒(a - 4)² + (b + 3)² + (c - 5)² = 0

⇒a = 4 , b = -3 and c = 5

so, the value of a + b² + c³ = 4 + (-3)² + 5³

= 4 + 9 + 125

= 138

Therefore the value of a + b² + c³ is 138.

Answer 2

Answer:

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