Question

If calorific fuel value of ethane is x kj/g then the heat of combustion of c2h6 is A) x B) 30x
C) x/30
D) 30/x

Answer 1

Answer: B) 30x

Explanation:

       Calorific Value = Amt of heat given out when one gram of substance is burnt completely in oxygen.

Therefore,   Calorific Value = $\frac{Heat released}{No. of grams}$

        No. of grams = No. of moles × Molecular mass

                               = 1 × 30

                               = 30g

Therefore,         Heat released = Calorific Value × No. of grams

                                                  = x × 30

                                                  = 30x

Answer 2

Answer:

30x

Explanation:

Just above explanation itself