Question

if car A is staring with initial velocity 0m/s and acceleration is 4 m/s^2 with time 0 second on the other hand car B is staring with initial velocity 0m/s and acceleration is 6m/s^2 with time 1 second so what is the time when two cars meet at one point?​

Answer 1

Answer:

1 second is the time when the two cars meet.

Explanation:

Car A: Using second Law of motion: s=ut+(1/2)at²

0*0+(1/2)4*0²

s=1/2m

Car B: Using second Law of motion: s=ut+(1/2)at²

0*1+(1/2)6*1²

s=3m

Therefore the point they will meet is,

In case of time it is 1-0= 1 second

In case of Distance it is 3-1/2=5/2=2.5m