If car A uses 35x2 + 3x – 4 litres of fuel to make a trip and car B uses 16x2 + 45x – 12
litres of fuel for the same trip, then find the extra quantity of fuel used by car A.
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Step-by-step explanation:
Given,
Fuel used by A = Fuel used by B
35x^2 + 3x -4 = 16x^2 + 45x -12
19x^2 -42x + 8 = 0
(x-2)(19x -4) = 0
So x = 2 or 4/19
Case 1 :- taking x = 4/19
Fuel used by A = 35*16/361 + 12/19 -4
= 1.55 + 0.63 - 4
Since, the fuel used cannot be in -ve, x ≠ 4/19.
Case 2 :- Now taking x = 2.
Fuel used by A = 35*4 + 6 -4
= 142 L
Fuel used by B = 16*4 + 45*2 -12
= 142 L
So, no extra fuel was used by A
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