Question

if car, mass 1485 kg, traveling south at 116 km/h, slows to stop in 10.25 second. what is the magnitude and direction of the net force that acted on the car?​

Answer 1

Given that:

• A car having mass 1485 kg, traveling south at 116 km/h.

To Find:

• Magnitude and direction of the net force that acted on the car to stop it in 10.25 second.

We know that:

• a = (v - u)/t
• F = ma

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time
• F = Force
• m = Mass

Converting initial velocity into m/s.

• 1 km/h = 5/18 m/s
• 116 km/h = (5 × 116)/18 = 290/9 m/s

Now we have:

• Final velocity = 0 m/s
• Initial velocity = 290/9 m/s
• Time = 10.25 s
• Mass = 1485 kg

Finding the acceleration:

ㅤ↠ㅤa = (v - u)/t

ㅤ↠ㅤa = (0 - 290/9)/10.25

ㅤ↠ㅤa = - 290/(10.25 × 9)

ㅤ↠ㅤa = - 290/92.25

ㅤ↠ㅤa = - (290 × 100)/9225

ㅤ↠ㅤa = - 29000/9225

ㅤ↠ㅤa = - (1160 × 25)/(369 × 25)

ㅤ↠ㅤa = - 1160/369

Finding the net force:

ㅤ↠ㅤF = ma

ㅤ↠ㅤF = 1485 × (- 1160/369)

ㅤ↠ㅤF = - (1485 × 1160)/369

ㅤ↠ㅤF = - 4668 (approx.)

Here,

• Negative sign shows that the force is in opposite direction.

Hence,

• Magnitude of net force is 4668 N.
• And the net force that acted on the car is in the north direction.

Answer 2

QUESTION :

• if car, mass 1485 kg, traveling south at 116 km/h, slows to stop in 10.25 second. what is the magnitude and direction of the net force that acted on the car?

GIVEN :

• if car, mass 1485 kg, traveling south at 116 km/h, slows to stop in 10.25 second

TO FIND :

• what is the magnitude and direction of the net force that acted on the car = ?

SOLUTION :

first we 1km/h we have 5/18 km/h

then, we will 5 multiply with 116 and divide

with 18 we get 290/9

we have to solve acceleration :

slows to stop in second = (0 - 290/9) / 10.25

stop in second = - 290 / (10.25 × 9)

• slows to stop in second = - 1160/369

then, we have to solve force :

• force we have = 1485(- 1160/369)

• force we have = - 4668

therefore :

so, force we have = - 4668

knowledge more :

first we have two formula for these questions :

• a = (v - u)/t

• F = ma

then, we have :

• v we will called as = final velocity

• u we called as = Initial velocity

• a we called as = Acceleration

• t we will Called as = time

• f we will Called as = force

• M we called as = mass