Question

if car Momentum increased by 20% then kinetic energy will be increased by​

Answer 1

Answer:

44%

Explanation:

We have,

K.E.=

2m

P

2

ΔK.E. =

2m

P

f

2

-

2m

P

i

2

=

2m

(

5

6P

)

2

-

2m

P

2

=

50m

36P

2

−25P

2

=

50m

11P

2

Now,

% Change =

KE

i

ΔKE

=

2m

P

2

50m

11P

2

×100

=

25

11

×100

=44%