Question

if carbon=24.2%h=4.21%find the remaining oxygen and if molecular weight=40 find Empirical formula and molecular formula​

Answer 1

Answer:

empirical formula : CH2,, molecular formula : C3H6

Explanation:

no.of moles in 24.2% of carbon= 24.2/12 = 2.016

no.of moles in 4.21% of h= 4.21/ 1 = 4.21

sample ratio :

2.016/2.016= 1

4.21/2.016= 2.088

therefore ratio is 1:2

so that empirical formula = CH2

m.f mass / e.f mass = 40 / 14 = 3 =[n]

so that m.f = e.f × n

=CH2 × 3

=C3H6

m.f is C3H6 ,, e.f is CH2

Answer 2

Answer:

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