If card is drawn from a pack of 52 cards find the probability of getting. 1 a black card .2 a not a black cards. 3 a cards bearing number between 2 to 5 including 2 and 5
Answers
Step-by-step explanation:
firstly in a pack of cards there 52 cards of 4 sets each having 13 cards of two colours red and black
=> 1. p(getting a black coloured card) =
no. of outcomes /total no. of outcomes
=black colour 2 sets so 26 cards
totals cards are 52
= 26/52 = 1/2
=> 2. p(of not getting black coloured card)
=26/52=1/2
=> 3. p(numbers btw 2 n 5)
= no. of outcomes are 2,3,4,5 each are in 4sets so there are 16 cards
=16/52= 4/13
Answer:
There are 52 cards in a pack
∴ n (S) = 52
(i) Let A be event that the card drawn a black card
Total no. of black cards = 26
∴ n (A) = 26
P (A) = n (A)/n (S)
∴ P (A) = 26/52
∴ P (A) = ½
(ii) Let B be the event that the card drawn is not a black card
Total no. of red cards = 26
∴ n (B) = 26
P (B) = n (B)/n (S)
∴ P (B) = 26/52
∴ P (B) = ½
(iii)Let C be the event that card drawn bears number between 2 and 5 including 2 and 5
No. of cards between 2 and 5 including 2 and 5 is 4.
∴ There are 4 types of cards
∴ The total no. of cards between 2 and 5 including 2 and 5 is 4 × 4 = 16
n (C) = 16
P (C) = n (C)/n (S)
∴ P (C) = 16/52
∴ P (C) = 4/13