Question

If Cartesian product A has 9 elements among which are found (-2,3) and (3,1). Find set A

Answer 1

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n( A × A ) = 9

Set A = { -2 , 1 , 3 }

$\sf\green{\underline{All\: Elements \:of\: (A × A)\: →}}$

{ (-2,-2) , (-2,1) , (-2,3) , (1,-2) , (1,1) , (1,3) , (3,-2) , (3,1) , (3,3) }

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Answer 2

$\displaystyle\huge\blue{\underline{\underline{ANSWER}}}$

n( A × A ) = 9

Set A = { -2 , 1 , 3 }

(A × A)

All elements (A×A) :-

{ (-2,-2) , (-2,1) , (-2,3) , (1,-2) , (1,1) , (1,3) , (3,-2) , (3,1) , (3,3) }