Question

if cas A=4/5 , than find the value of tan A & sin A​

Answer 1

$\star\:\:\:\sf\large\underline\blue{Question:-}$

• If $\sf \cos(x) = \frac{4}{5}$, then find the value of $\sf \tan(x)$ and $\sf \sin(x)$

$\star\:\:\:\sf\large\underline\blue{Solution:-}$

We know that,

$\sf { \sin}^{2} (x) + { \cos }^{2} (x) = 1$

$\sf { \sin}^{2} (x) = 1 - { \cos }^{2} (x)$

$\sf { \sin} (x) = \sqrt{1 - { \cos }^{2} (x) }$

Therefore,

$\sf \sin(x)$

$\sf = \sqrt{1 - \frac{ {4}^{2} }{ {5}^{2} } }$

$\sf = \sqrt{ \frac{ 25 - 16 }{ 25} }$

$\sf = \sqrt{ \frac{ 9 }{ 25} }$

$\sf = \frac{3}{5}$

Therefore,

$\sf \sin(x) = \frac{3}{5}$

So,

$\sf \tan(x) = \frac{ \sin(x) }{ \cos(x) }$

$\sf= \frac{3}{5} \div \frac{4}{5}$

$\sf = \frac{3}{4}$

So,

$\sf \tan(x) = \frac{3}{4}$

$\star\:\:\:\sf\large\underline\blue{Answer:-}$

$\sf \sin(x) = \frac{3}{5}$

$\sf \tan(x) = \frac{3}{4}$

Answer 2

Answer:

tanA = 3/4

sinA = 3/5

HOPE YOU AGREE.