Question

if centre of a circle is (2,3) and point of diameter is (3,2) then the coordinate of the other of the other end point is​

Answer 1

Step-by-step explanation:

centre is the mid point of the end points of a diameter

let the other end of the diameter be (x,y)

therefore, (2,3)=((3+x)/2,(2+y)/2)

2=(x+3)/2

->x+3=4

->x=1

and

3=(y+2)/2

->y+2=6

->y=4

therefore the other end is (x,y) = (1,4)

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Answer 2

Answer: let the coordinates of other end be (x,y)

As (2,3) is the mid point therefor we use,

(2,3)=[(3+x)/2,(2+y)/2]

Equating both sides,

2=(3+x)/2 And 3=(2+y)/2

4=3+x 6=2+y

x=1 y=4

So the coordinates are (1,4)

Hope this answer will help you