If CH3COOH + OH- = CH3COO- + H2O + Q1 and H+ + OH- = H2O + Q2
then enthalpy change for the reaction
CH3COOH= CH3COO- + H+ is equal to
a) Q1+ Q2 b) Q1-Q2 c) Q2- Q1 d) -(Q1+Q2);
with explanation please.
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Answer:option c
Explanation:
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