if chances of A, winning a race is 1/6, 3 winning the same race is 1/3, what is the chances both will win if winning at least is 2/3?
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It is 12 .
If they both join the same competition,
P(A lose and B lose) =1−16−13=12.
Let’s see what confuses people.
When A and B are joining different competitions,
P(A loses) =1−13=23
P(B loses) =1−16=56
P(A and B lose)
= P((A loses) ∩ (B loses))
= P(A loses) × P(B loses)
=23×56
=59
I HOPE IT'S HELPFULL
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