Question

If change in energy
(AE) = 3 x 10-8 J, h - 6.64 x 10-34 J-s and
c = 3 x 108 m/s, then wavelength of the light is.
(1) 6.64 x 103 A (2) 6.64 x 105 A
(3) 6.64 x 10-8 Å (4) 6.64 x1018​

Answer 1

Answer:

By Planck's quantum theory

E=h*c/lambda. (frequency= c/lambda)

3*10^-8=6.64*10^-34*3*10^8/lambda

10^-8=6.64*10^-26/lambda

lambda=6.64*10^-26+8

lambda=6.64*10^-18 metres

lambda=6.64*10^-8*10^-10

lambda=6.64*10^-8 Angstroms. (1 angstrom=10^-10metres

so wave length is 6.64*10^-8 Angstrom.

option (3).

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