Question

if change in energy (delta E) = 3*10 to the power -8 J h= 6.64* 10 to the power -34 J-s and c= 3*10 to the power 8 m/s then wavelength of the light

Answer 1

if change in energy (delta E) = 3 × 10^-18 J, h= 6.64 × 10^-34 J-s and c= 3× 10^8 m/s then wavelength of the light.

energy change , ∆E = hc/$\lambda$ where h is plank's constant , c is velocity of light and $\lambda$ is wavelength.

here h = 6.64 × 10^-34 Js

c = 3 × 10^8 m/s and ∆E = 3 × 10^-18 J

now, 3 × 10^-18 = 6.64 × 10^-34 × 3 × 10^8/$\lambda$

or, $\lambda$ = 6.64 × 10^-34 × 10^26

= 6.64 × 10^-8 m

hence, wavelength of the light is 66.4 nm

Answer 2

Answer:

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