Question

If change in energy (ΔE) = 3×10–8 J,h = 6.64 ×10–34 J-S and C = 3×10–8 m/s then wavelength of the light is

Answer 1

if change in energy (delta E) = 3 × 10^-18 J, h= 6.64 × 10^-34 J-s and c= 3× 10^8 m/s then wavelength of the light.

energy change , ∆E = hc/ where h is plank's constant , c is velocity of light and is wavelength.

here h = 6.64 × 10^-34 Js

c = 3 × 10^8 m/s and ∆E = 3 × 10^-18 J

now, 3 × 10^-18 = 6.64 × 10^-34 × 3 × 10^8/

or, = 6.64 × 10^-34 × 10^26

= 6.64 × 10^-8 m

hence, wavelength of the light is 66.4 nm