Question

If charge on a body is 2 nC, then how many electrons are absent from the body?​

Answer 1

Explanation:

q=ne

2×10^-9=n×1.6×10^-19

n=1.25×10^10 electrons

Answer 2

Given:

The charge on a body is 2 nC.

To find:

Number of electrons absent from the body?

Calculation:

• Let the number of electrons absent be 'n'.

Now, we know that charge on a body is equal to integral multiples of charge of a single electron.

$\rm \: Q = n \times e$

$\rm \implies \: 2 \times {10}^{ - 9} = n \times (1.6 \times {10}^{19} )$

$\rm \implies \: n = \dfrac{2 \times {10}^{ - 9} }{1.6 \times {10}^{ - 19} }$

$\rm \implies \: n = 1.25 \times {10}^{10}$

$\rm \implies \: n = 125 \times {10}^{7} \: electrons$

So, 125 × 10⁷ electrons are absent