If charges for subsequent hours is ₹8 per hour, then write linear equation (a) 10x - y +8=0 (b)10x - y +10=0 (c)8x-y + 14 =0 (d)8x - y +8=0
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Let total hours =x, total charges =y
Charges for 2hrs =Rs. 50
Charges for more than 2hrs =Rs. 10.
Remaining hours =x−2
Total charges for remaining hours =Rs. 10(x−2)
Total charges = charge for first 2 hrs + charge for remaining hours
⇒y=50+10(x−2)
⇒y=30+10x.
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