If charges for subsequent hours is Rs.8 per hour, then write linear equation
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Answer:
Car parking is a major problem in urban areas in both developed and
developing countries .In Jaipur city GT mall is shopping place charged the parking
lot is ₹30 for the first two hours and ₹10 per hour for subsequent hours, then answer
the following questions.
(i) Taking total parking time to be x hour, and total charges as ₹ y. Write a linear
equation.
(a) 10x+y-10=0 (b) 10x-y+10=0 (c) 8x+y-10=0 (d)
8x-y+10=6
(ii) If y=20, then value of x
(a) 1 (b) 2 (c) 3 (d) 4
(iii) If x=2, then value of y is
(a) 10 (b) 20 (c) 30 (d) 40
(iv) If the charges of a car in a parking lot is ₹ 50 for first two hours, then find the
linear equation.
(a) 10x-y+30=0 (b) 10x+y+30=0 (c) 10x+y-30=0 (d)
30x+y-10=0
(v) If charges for subsequent hours is ₹ 8 per hour, then write linear equation.
(a) 10x-Y+8=0 (b) 10x-Y+10=0 (c) 8x-y+14=0 (d) 8x-y+8=0
If charges for subsequent hours is ₹ 8 per hour, then write linear equation.
(a) 10x-Y+8=0 (b) 10x-Y+10=0 (c) 8x-y+14=0 (d) 8x-y+8=0
Let total hours =x, total charges =y
Charges for 1hrs =Rs. 8
Charges for more than 1hrs =Rs. 8
Remaining hours =x−1
Total charges for remaining hours =Rs. 8(x−1) +8