Math, asked by god1324219, 14 hours ago


If charges of a car in a parking lot is Rs. 50 for the first two hours, then find the linear equation
(a) 10x - y + 30 = 0
(b) 10x + y + 30 = 0
( 10x + y - 30 = 0
(d) 30x + y - 10 = 0
hour, then write linear equation.​

Answers

Answered by ananypawar1
3

Answer:

ANSWER IS 10x-y+30=0

Step-by-step explanation:

NOTHING TO SAY

Answered by anjumanyasmin
3

Given:

the parking charges of a car for first two hours is Rs. 50 and Rs. 10 for each subsequent hour.

⇒ the extra charges for first two hours apart from Rs. 10 per hour = 50-(10× 2)

= 30

Now, let ‘x’ be no. of hours and ‘y’ be the parking charges.

⇒ y = 10x + 30 is the equation.

10x-y+30=0

The correct option is "a"

Hence the linear equation is 10x-y+30=0

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