If charges of a car in a parking lot is Rs. 50 for the first two hours, then find the linear equation
(a) 10x - y + 30 = 0
(b) 10x + y + 30 = 0
( 10x + y - 30 = 0
(d) 30x + y - 10 = 0
hour, then write linear equation.
Answers
Answered by
3
Answer:
ANSWER IS 10x-y+30=0
Step-by-step explanation:
NOTHING TO SAY
Answered by
3
Given:
the parking charges of a car for first two hours is Rs. 50 and Rs. 10 for each subsequent hour.
⇒ the extra charges for first two hours apart from Rs. 10 per hour = 50-(10× 2)
= 30
Now, let ‘x’ be no. of hours and ‘y’ be the parking charges.
⇒ y = 10x + 30 is the equation.
10x-y+30=0
The correct option is "a"
Hence the linear equation is 10x-y+30=0
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