If Chinua starts with 10 g of magnesium, how much magnesium
will be present in the magnesium sulfate?
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Answer:
Explanation:
Molar mass of MgSO4=120 g/mol
Percentage of Mg inMgSO4 = (10/120)×100= 100/12 = 50/6= 25/3=8.33%
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