Question

if circles are drawn taking two sides of a triangle as diameter prove that the point of intersection of these circle lie on the third sides​

Answer 1

Answer:

Given,

Two circles are drawn on the sides AB and AC of the triangle  

ABC as diameters. The circles intersected at D.

Construction: AD is joined.

To prove: D lies on BC. We have to prove that BDC is a straight line.

Proof:

∠ADB=∠ADC=90°        ...Angle in the semi circle

Now,

∠ADB+∠ADC=180°

⇒∠BDC is straight line.

Thus, D lies on the BC.

Step-by-step explanation:

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