if circumference of a circle is 400cm.Find the perimeter of rectangle whose length is double of its breadth and breadth is twice of radius
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Answered by
1
Answer:
Step-by-step explanation:
circumference = 400cm
2πr = 400cm
πr = 200 cm
r = 200* 7/22
r = 700/11 cm
breadth of rect. (b) = 2r
length of rectangle (l) = 2b = 4r
perimeter of rectangle = 2(l+b)
= 2( 4r + 2r )
=2 ( 6r )
= 12r
= 12 * 700/11
=8400/11
=763.6 cm
PLEASE MARK THIS AS BRAINLIEST ANSWER !
moksha41:
it's 763.2 cm
Answered by
1
We know that, circumference of circle =
2 x 22/7 x r = 400
r = 200 x 7 / 22
r = 1400 / 22
r = 700 / 11
Thus, radius of circle is 700/11 cm
• Perimeter of Rectangle
Perimeter = 2(l+b)
Breadth = 2r
= 2 × 700 / 11
= 1400 / 11
Length = 2 × b
= 2800 / 11
Now, perimeter = 2(2800/11 + 1400/11)
= 2(4200/11)
= 8400 / 11
= 763.63 cm
Hope this helps you!
2 x 22/7 x r = 400
r = 200 x 7 / 22
r = 1400 / 22
r = 700 / 11
Thus, radius of circle is 700/11 cm
• Perimeter of Rectangle
Perimeter = 2(l+b)
Breadth = 2r
= 2 × 700 / 11
= 1400 / 11
Length = 2 × b
= 2800 / 11
Now, perimeter = 2(2800/11 + 1400/11)
= 2(4200/11)
= 8400 / 11
= 763.63 cm
Hope this helps you!
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