If cl ab and (b, c) = 1 then prove that c|a .
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Answer: Given, a+b+c=0
and ∣a∣=5,∣b∣=3,∣c∣=7
⇒a+b=c
On squaring both sides, we get
(a+b)
2
=(−c)
2
⇒∣a+b∣
2
=∣c∣
2
⇒∣a∣
2
+∣b∣
2
+2a⋅b=∣c∣
2
(∵θ be the angle between a and b)
⇒(5)
2
+(3)
2
+2∣a∣∣b∣cosθ=(7)
2
⇒25+9+2⋅5⋅3cosθ=49
⇒30cosθ=15
⇒cosθ=
2
1
=cos60
∘
⇒θ=
3
π
Step-by-step explanation:
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