Question

if class mark is 10 and class width is 6 then find the class

Answer 1

let the lower limit be x,
then upper limit will be x+6.
then, ATQ—
$\frac{(x) + (x + 6)}{2} = 10$
or
$\frac{2(x + 3)}{2} = 10$
or
$x = 10 - 3$
so, x=7
so lower limit is 7.
upper limit is 7+6=13.

Please mark my answers as brainliest if you got help.

Answer 2

Answer:

We have, class mark = 10 and class width = 6.

Since, 6/2=3

The lower class limit = 10−3=7 and the upper class limit = 10+3=13.

So, the class is 7-13.