Question

If class mark is 20 and class width is 8 then find the class ​

Answer 1

Step-by-step explanation:

Let Lower Limit be L

∴ Upper Limit =L+10 [ Since, Class Width =10]

Now, we know that

ClassMark=(LowerLimit+UpperLimit)÷2

∴ (L+L+10)÷2=25 [Class Mark 25 given]

⇒ 2L+10=50

⇒ 2L=40

⇒ L=20

∴ Lower Limit of the class =20

Upper Limit of the class =20+10=30

The required class is 20−30

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Answer 2

Thanks for your question...

Your required answer :

Given :

• Class mark = 20
• Class width = 10

To find :

• Class

Solution :

$\frac{8}{2} = 4$

So :

• Lower limit = 20 - 4 = 16
• Upper limit = 20 + 4 = 24

So the class is :

• 16 - 24

Brainliest Please