Question

if class of 20 students the average marks of the first 19th student is 25 and the lost 19 is 26 if the first was get 16 marks find the marks of last boy​

Answer 1

Answer:

Step-by-step explanation:

Average = $\frac{Sum of the numbers }{Number of numbers}$

Lets represent the marks by letters

$\frac{a+b+c+d+e+f+g+h+i+j+k+l+m+n+o+p+q+r+s}{19}$ = 25

So,

a+b+c+d+e+f+g+h+i+j+k+l+m+n+o+p+q+r+s = 19 x 25

                                                                          = 475

Now the sum of last 19 numbers = $\frac{b+c+d+e+f+g+h+i+j+k+l+m+n+o+p+q+r+s+t}{19}$=26

So,

b+c+d+e+f+g+h+i+j+k+l+m+n+o+p+q+r+s+t = 19 x 26 = 494

Now

a = 16

So,

b+c+d+e+f+g+h+i+j+k+l+m+n+o+p+q+r+s = 475-16= 459

So,

t = 494-459 = 35

Hope this helps

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