Question

if cofficient of variations of two standard distribution are 30 and 50 and their standard deviations are 12 and 15 respectively . find their arthmetic means

Answer 1

Step-by-step explanation:

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Answer 2

Arithmetic Mean of first distribution = 40

Arithmetic Mean of second distribution = 30

Step-by-step explanation:

We are given that coefficient of variations of two standard distribution are 30 and 50 and their standard deviations are 12 and 15 respectively.

As we know that Coefficient of variation formula is given by;

      Coefficient of Variation = $\frac{S.D.}{Mean} \times 100$  , where S.D. = Standard deviation

Now, let standard deviation of first distribution = $S.D_1$ = 12

        Standard deviation of second distribution = $S.D_2$ = 15

Also, Coefficient of variation of first distribution = $CV_1$ = 30

        Coefficient of variation of second distribution = $CV_2$ = 50

• So, Arithmetic mean of first distribution is;

                   $CV_1 = \frac{S.D_1}{Mean_1} \times 100$

                   $30 = \frac{12}{Mean_1} \times 100$

                   $Mean_1 = \frac{12}{30} \times 100$

                   $Mean_1 = \frac{120}{3}$ = 40

Therefore, Arithmetic Mean of first distribution, $Mean_1$ = 40

• Arithmetic mean of first distribution is;

                   $CV_2 = \frac{S.D_2}{Mean_2} \times 100$

                   $50 = \frac{15}{Mean_2} \times 100$

                   $Mean_2 = \frac{15}{50} \times 100$

                   $Mean_2 = \frac{150}{5}$ = 30

Therefore, Arithmetic Mean of second distribution, $Mean_2$ = 30.