Question

If common difference d=-4 and
first term a=0 then write four
terms of an AP
​

Answer 1

Answer:

$\boxed{\bf 0,-4,-8,-12,-16,....}$

Step-by-step explanation:

$Given,\\ common \ difference,d=-4 \\ first \ term,a=0 \\\\\\ In \ an \ AP, \\ \boxed{\bf n^{th} \ term,a_n\\= a+(n-1)d} \\\\ => first \ term,a_1=0 \\\\ =>second \ term,\\ a_2=0+(2-1)(-4) \\ \ \ \ \ a_2 =1(-4) \\ a_2=-4 \\\\ =>third\ term, \\a_3=0+(3-1)(-4) \\a_3=2(-4) \\ a_3=-8 \\\\ =>fourth \ term,\\a_4=0+(4-1)(-4) \\a_4=3(-4) \\a_4=-12 \\\\ fifth \ term,\\a_5=0+(5-1)(-4) \\a_5=4(-4)\\a_5=-16$