Question

If compound interest on a certain sum of money at 5% per annum for 2 years is Rs. 246. The simple interest on the same sum for 4 years at 8% per annum is​

Answer 1

_____________________________________________

$\\ \large \sf \: on \: \: interest \: \: be \: \: compounded \: \\ \large \sf \: for \: \: 2 \: years \: \: and \: \: r = 5\% \\ \\ \large \underline{\sf using \: \: formula : } \\ \\ \large \sf \: ammount = p \left(1 + \frac{r}{100} \right )^{n} \\ \\ \large \sf : \implies \: a = p \left( 1 + \frac{5}{100} \right) ^{2} \\ \\ \large \sf : \implies \: a = p \left( \frac{100 + 5}{100} \right) ^{2} \\ \\ \large \sf : \implies \: a = p \left( \frac{105}{100} \right) ^{2} \\ \\ \large \sf : \implies \: a = p \times (1.05 {)}^{2} \\ \\ \large \sf \therefore \underline{ \: a = 1.1025p} \\ \\ \large \sf \: so. \\ \\ \large \sf \: c.l \: = a - p \\ \\ \large \sf : \implies \: c.l = 1.1025p - p \\ \\ \large \sf \therefore \: c.l = 0.1025p \\ \\ \large \sf \: given. \\ \\ \large \sf \mapsto \: c.l = rs. \: 246\\ \\ \large \sf \implies \: 0.1025 p= 246246\\ \\ \large \sf \implies \: p= \frac{246}{0.1025} \\ \\ \large \sf \therefore \: \underline{ \: p = rs. \: 2400} \\ \\ \large \sf \: for. \\ \\ \large \sf \: p = rs. \: 2400 \\ \\ \large \sf \: \large \sf \: n = 3 \: years \\ \\ \large \sf \: \large \sf \:r = 6\% \\ \\ \large \sf \: \mapsto \: s.i = \frac{p \times n \times t}{100} \\ \\ \large \sf : \implies \: s.i = \frac{2400 \times 6 \times 3}{100} \\ \\ \large \sf : \implies \: s.i = \frac{24 \cancel{00 }\times 6 \times 3}{1 \cancel{00} } \\ \\ \large \sf \implies \: s.i = 24 \times 6 \times 3 \\ \\ \large \sf \therefore \: \underline{simple \: \: interest = rs. \: 432}$

Answer 2

Answer:

mark me as Brainliest and thank me if the answer is useful.

Step-by-step explanation: