Question

If concentration of oh- is 10^-2 then what is the ph

Answer 1

Answer:

Explanation:

Method 1:

we know that [H+] * [OH-] = 10^(-14)

[H+] * 10^(-2) = 10^(-14). so [H+] is 10^(-12)

pH = - log [H+] = - log 10^(-12) = 12

Method 2:

pOH = - log [OH-] = - log 10^(-2) = 2

pH + pOH = 14

pH + 2 = 14

pH = 12