Question

If cone, of reactant ‘A’ is increased 10 times and rate of reaction becomes 100 times. What is order with respect to ‘A’?
(a) 1
(b) 1
(c) 3
(d) 4

Answer 1

Answer:

a is the correct answer

Explanation:

hope it's help you thank you

Answer 2

Given:

The concentration, of reactant ‘A’, is increased 10 times and the rate of reaction becomes 100 times.

To find:

We have to find the order.

Solution:

Let us take a reaction reactant A reacts to form product P.

Let the order of the reaction is x.

So, we can write the rate expression as-

$R=k.[A]^x$

The concentration, of reactant ‘A’, is increased 10 times and the rate of reaction becomes 100 times.

$100R=k.[10A]^x$

Now we can write-

$\frac{100}{1} = { \frac{10}{1} }^{x} \\ {10}^{2} = {10}^{x} \\ x = 2$

The value of x is 2.

Hence the order of the reaction is 2.