Question

If convex lens of focal length 30 cm is immersed in a liquid of refractive index 1.5 can new focal length of the mirror will be

Answer 1

Hey there,

By lensmakers formula,

❇ 1/f=(µ-1)(1/R1-1/R2)

Now,

✔✔f1=30 cm,µ1=1.5,µ2=1.33.f2=?

=>(1/f1)/(1/f2)=(µ1-1)/(µ2-1).(dividing_
[:1/R1-1/R2 remain same]]

=>f2/30=0.5/0.33

=>f2=30×3/2=45 cm.

✔f2=45 cm

Hope it helps.

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