If COO(s)+H2O) = Co(s)+H2O(g), K = 60; COO(s) + CO(g) = Co(s) + CO2(g), K2 = 180 then the equilibrium
constant of the reaction CO2(g) +H2(g) = CO(g) +H,O(g) will be-
(1) 0.44
(2) 0.11
(3) 0.22
(4) 0.33
Answers
Answered by
22
Answer:
(4) 0. 33
Explanation:
k1×1/K2
60/180
0. 33
Answered by
3
Answer:
kc =60*1/180=0.33
so kc is 0.33
answer
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