If coordinate of A and B is (0,0) and (9,0) respectively then find point which divide ab externally in 1 ratio 2, and find its harmonic conjugate also.
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Answer:
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- The point which divide AB externally in the ratio 1 : 2 is ( - 9,0)
- The harmonic conjugate of the point is (3,0)
Given :
The coordinate of A and B is (0,0) and (9,0) respectively
To find :
- The point which divide AB externally in the ratio 1 : 2
- The harmonic conjugate of the point
Formula Used :
1. The coordinates of the point where the line joining the points (x₁ , y₁) & (x₂ , y₂) is divided Internally in the ratio m : n
2. If a point P divides AB in the ratio m : n externally then harmonic conjugate divides AB internally in the ratio m : n
Solution :
Step 1 of 3 :
Write down the given points
Here the given points are A(0,0) , B(9,0)
Step 2 of 3 :
Find the point which divide AB externally in the ratio 1 : 2
We know that , the coordinates of the point where the line joining the points (x₁ , y₁) & (x₂ , y₂) is divided externally in the ratio m : n is
∴ The coordinate of the point which divide AB externally in the ratio 1 : 2
Step 3 of 3 :
Find the harmonic conjugate of the point
Since the point which divide AB externally in the ratio 1 : 2
∴ The harmonic conjugate of the point will divide AB internally in the ratio 1 : 2
Hence harmonic conjugate of the point
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