if coordinate of mid point of side of triangle are(2,1) (3,-5) (6,4) find its centroid
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A(2,1),B(3,-5),and C(6,4)
Here,
X1=2,X2=3,X3=6
and,
Y1=1,Y2=-5,and Y3=4
G= (X1+X2+X3/3,Y1+Y2+Y3/3)
= (2+3+6/3) , (1+(-5)+4/3)
= 11/3,0/3
Centroid = 11/3,0/3
Here,
X1=2,X2=3,X3=6
and,
Y1=1,Y2=-5,and Y3=4
G= (X1+X2+X3/3,Y1+Y2+Y3/3)
= (2+3+6/3) , (1+(-5)+4/3)
= 11/3,0/3
Centroid = 11/3,0/3
sanyam051:
thanks but ans is (11/3 , -7/6)
and the ans u have derivated is also wrong as 1-5+4=0 not 8
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