Question

If coordinates of A, B, C D are (2,1),(0,-1), (-1,8), (4,3), then
(MAB)(MCD)...............​

Answer 1

Given : coordinates of  A, B, C D are (2,1),(0,-1), (-1,8), (4,3)

To Find :  $(m_{AB})(m_{CD})$

Solution:

A(2 , 1)

B (0 , - 1)

$(m_{AB}) = \dfrac{-1 - 1}{0-2}$

$\implies (m_{AB}) = \dfrac{-2}{ -2}$

$\implies (m_{AB}) = 1$

C(-1,8)

D(4,3)

$(m_{CD}) = \dfrac{8 - 3}{-1-4}$

$\implies (m_{CD}) = \dfrac{5}{ -5}$

$\implies (m_{CD}) = -1$

$(m_{AB})(m_{CD}) =(1)(-1)$

$\implies (m_{AB})(m_{CD}) = -1$

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