Question

if coordinates of two adjacent vertices of a parallelogrm are (3,2),(1,0) and diagonals bisect each other at (2,-5) find corrdinayes of other two besrtices.​

Answer 1

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Answer:

Let the coordinates of C and D be (a,b) and (c,d).

$\frac{3 + a}{2} = 2 \\ a = 1 \\ \\ \frac{2 + b}{2} = - 5 \\ b = - 12 \\ \\ \frac{c + 1}{2} = 2 \\ c = 3 \\ \\ \frac{d + 0}{2} = - 5 \\ d = - 10$

Coordinates of C and D are (1,-12) and (3,-10).

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Answer 2

Step-by-step explanation:

Let the coordinates of C and D be (a, b) and (c, d)

∴ (3 + a)/2 = 2

=> a = 1

and (2 + b)/2 = –5

=> b = –12

similarly

(c + 1)/2 = –5

=> c = 3

and (d + 0)/2 = –5

=> d = –10

hence:-

Coordinate of C and D are (1, –12) and (3,–10)

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