Question

if cos=0.6,show that (5sinq-3tanq)=0

Answer 1

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Answer 2

Given $\cos q=0.6$. So $\sin q=\sqrt{1-\cos^2 q} =\sqrt{1-0.6^2} =\sqrt{0.64} =0.8$

Also, $\tan q=\frac{\sin q}{\cos q} =\frac{0.8}{0.6} =\frac{4}{3}$.

$LHS=5 \sin q-3 \tan q=5(0.8)-3(\frac{4}{3} )\\ LHS=4-4=0=RHS$

The proof is complete.