if cos 0 + sin 0 = 2 cos 0 .show that ( cos 0- sin 0) = 2 sin 0
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Answer:
Given
cosθ+sinθ=
2
cosθ
squaring on both the sides, we get,
cos
2
θ+sin
2
θ+2sinθcosθ=2cos
2
θ
cos
2
θ−sin
2
θ=2cosθsinθ
(cosθ+sinθ)(cosθ−sinθ)=2cosθsinθ
2
cosθ(cosθ−sinθ)=2cosθsinθ [ Given cosθ+sinθ=
2
cosθ]
∴cosθ−sinθ=
2
sinθ [henceproved]
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