Question

If cos(α+β)=0, then sin(α-β) can be reduced to

Answer 1

Answer:

sin(α-β) can be reduced to $\cos 2b$

Step-by-step explanation:

cos(α+β)=0 implies that (α+β) = 90

Which means α = 90-β

Putting this in sin(α-β) we get sin(90-β-β) = sin(90-2β) = cos 2β

That's it.