If |cos^(-1)x|<(pi)/(3) then the set of exhaustive values of x is
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Given : | cos⁻¹ x | < π/3
To Find : values of x
Solution:
Principle Range of cos⁻¹ is [0 , π]
Hence | cos⁻¹ x | = cos⁻¹ x
cos⁻¹ x < π/3
cos⁻¹ (1/2) = π/3
cos⁻¹ (√3 / 2) = π/6
cos⁻¹ 1 = 0
Hence x ∈ (1/2 , 1]
x ∈ (1/2 , 1]
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