Question

if cosθ=12/13, then find tanθ and cosecθ
​

Answer 1

Answer:

tan θ = 5/12

cosec θ = 13/5

Step-by-step explanation:

Given that,

• cos θ = 12/13

⇒ cos θ = Base/Hypotenuse

Firstly, we need to calculate perpendicular.

$\longrightarrow$ H² = B² + P²

$\longrightarrow$ (13)² = (12)² + P²

$\longrightarrow$ 169 = 144 + P²

$\longrightarrow$ 169 - 144 = P²

$\longrightarrow$ 25 = P²

$\longrightarrow$ √25 = P

$\longrightarrow$ 5 = Perpendicular

Now, we know that,

$\longrightarrow$ tan θ = Perpendicular/Base

$\longrightarrow$ tan θ = 5/12

And,

$\longrightarrow$ cosec θ = Hypotenuse/Perpendicular

$\longrightarrow$ cosec θ = 13/5

______________________________

More Formulae :

• sin θ = Perpendicular/Hypotenuse

• cos θ = Base/Hypotenuse

• tan θ = Perpendicular/Base

• cosec θ = Hypotenuse/Perpendicular

• sec θ = Hypotenuse/Base

• cot θ = Base/Perpendicular

______________________________