if cos-1x + cos-1y + cos-1z = pi
prove that x2 + y2 + z2 +2xyz = 1
Answers
Answered by
3
Let cos-1x =A then x= cosA
Let cos-1y=B then y =cosB
Let cos-1z=C then z=cosC
Then A+B+C =p
Xv(1-X2) +Yv(1-Y2) +Zv(1-Z2)=cosA v(1-cos2A)+cosBv(1-cos2B) +cosCv(1-cos2C)
=CosA.sinA+cosB.sinB+cosC.sinC
=1/2[cos2A+cos2B+cos2C]
=1/2 [4cosA.cosB.cosC]
=2cosA.cosB.cosC
=2xyz
Similar questions