Question

if cos^-1x>2 +cos^-1y + cos^-1z =0 then value of xyz is

Answer 1

Step-by-step explanation:

Answer

cos

−1

x+cos

−1

y+cos

−1

z=π

cos

−1

x+cos

−1

y=π−cos

−1

z

cos

−1

(xy−

1−x

2

1−y

2

)=π−cos

−1

z

xy−

1−x

2

1−y

2

=cos(π−cos

−1

z)

xy−

1−x

2

1−y

2

=−cos(cos

−1

z)

xy−

1−x

2

1−y

2

=−z

xy+z=

1−x

2

1−y

2

(xy+z)

2

=(1−x

2

)(1−y

2

)

x

2

y

2

+z

2

+2xyz=1−x

2

−y

2

+x

2

y

2

x

2

+y

2

+z

2

+2xyz=1