Question

if cos ө = 21/ 29 , then the value of secө / (tan ө -sin ө)

Answer 1

Answer: 17661/3360

Step-by-step explanation:

cosθ=21/29

$29^{2}$ = $21^{2}$ + $x^{2}$

∴ x = √(841 - 441)

     = √400 = 20

∴ sinθ=20/29

⇒ tanθ=(20/29)÷(21/29) = (20/29)×(29/21) = 20/21

From cosθ = 1/secθ

⇒ secθ = 29/21

substituting the values:

secө / (tan ө -sin ө) = (29/21) / (( 20/21) - (20/29))

                                = (29/21) / (( 580-420 )/609)

                                = (29/21) / (160/609)

                                = (29/21) × (609/160)

                                = 17661/3360