Question

if cos 28′+sin28′=k^3 then cos 17 is equal to​

Answer 1

Answer:

k^3/√2

Step-by-step explanation:

cos 28'+sin (90'-62')=k^3

sin(90'-theta)=cos theta

cos 28'+cos 62'=k^3

cos 62'+cos 28'=k^3

cosC+cosD= 2cos(C+D) cos(C+D)

2cos90' cos34 =k^3

2. 2

2cos45' cos17'=k^3

2*1/√2 cos 17'=k^3

√2cos17'=k^3

cos17'=k^3/√2