If cos 2a = sin a, then value of tan 2a. is
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cos (A + B) = cos A cos B - sin A sin B
Now, putting B = A on both sides of the above formula we get,
cos (A + A) = cos A cos A - sin A sin A
⇒ cos 2A = cos2 A - sin2 A
⇒ cos 2A = cos2 A - (1 - cos2 A), [since we know that sin2 θ = 1 - cos2 θ]
⇒ cos 2A = cos2 A - 1 + cos2 A,
⇒ cos 2A = 2 cos2 A - 1
⇒ cos 2A = 2 (1 - sin2 A) - 1, [since we know that cos2 θ = 1 - sin2 θ]
⇒ cos 2A = 2 - 2 sin2 A - 1
⇒ cos 2A = 1 - 2 sin2 A
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