If cos 2theta = sin 4theta; here 2theta and 4theta are
acute angles, then the value of 'theta' is
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Given,
2 θ and 4 θ are acute and cos2θ=sin4θ
We have, cosθ=sin(90 ∘ −θ)
cos2θ=sin(90 ∘ −2θ)
∴sin(90 ∘ −2θ)=sin4θ
90 ∘ −2θ=4θ
90 ∘ =2θ+4θ
6θ=90 ∘
θ=15 ∘
hope this helps you ✌️
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