Question

if cos = √3/2 than find sin ,tan

please ans​

Answer 1

Answer:

1/2 and 1/√3

Step-by-step explanation:

cos = b/h

hence, b=√3 and h=2

hence, p=√(h²-b²) = √(4-3) = 1

hence sin=p/h = 1/2

tan=p/b = 1/√3

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Answer 2

Answer:

sin = 1/2

tan = 1/√3

Step-by-step explanation:

$cos=\frac{\sqrt{3} }{2} =\frac{Base}{Hypotenuse}$

Base(B) = √3

Hypotenuse(H) = 2

Applying pythagoras theorem,

(H)² = (P)² + (B)²

(P)² = (H)² - (B)²

(P)² = (2)² - (√3)²

(P)² = 4 - 3

P = √1

P = 1

Perpendicular(P) = 1

$sin=\frac{P}{H} =\frac{1}{2}$

$tan = \frac{P}{B} =\frac{1}{\sqrt{3} }$